

Call For Moderators
#152
Posted 07 June 2005 - 02:28 PM

BF2 Hackers =5SF= have busted
]sD[ Engageo <-- couldn't get him banned though, no screenshot of him ingame
]sD[Nomisser
an AK guy
The anti-logarithm of the logarithm of X plus the logarithm of Y equals X times Y, or 10^(logX + logY) = XY

I hate spider solitaire...
#154
Posted 07 June 2005 - 02:48 PM
edit: actually, i was playing not too long ago, and i got my first devastator the first thursday of the game

Edited by blehm, 07 June 2005 - 04:48 PM.
BF2 Hackers =5SF= have busted
]sD[ Engageo <-- couldn't get him banned though, no screenshot of him ingame
]sD[Nomisser
an AK guy
The anti-logarithm of the logarithm of X plus the logarithm of Y equals X times Y, or 10^(logX + logY) = XY

I hate spider solitaire...
#155
Posted 07 June 2005 - 03:49 PM

Be prepared for a hard game.
Take one more step, and I swear, I will kill you so hard you will die to death.
#158
Posted 08 June 2005 - 12:56 PM
i only spam because tsereve brings it up and i can't let him spread lies
BF2 Hackers =5SF= have busted
]sD[ Engageo <-- couldn't get him banned though, no screenshot of him ingame
]sD[Nomisser
an AK guy
The anti-logarithm of the logarithm of X plus the logarithm of Y equals X times Y, or 10^(logX + logY) = XY

I hate spider solitaire...
#162
Posted 14 July 2005 - 01:25 AM
I can speak and read english, davidian, and some Binary, so no language forums, and i don't happen to have a spare babelfish or translater at my side
Edited by blehm, 14 July 2005 - 01:27 AM.
BF2 Hackers =5SF= have busted
]sD[ Engageo <-- couldn't get him banned though, no screenshot of him ingame
]sD[Nomisser
an AK guy
The anti-logarithm of the logarithm of X plus the logarithm of Y equals X times Y, or 10^(logX + logY) = XY

I hate spider solitaire...
#168
Posted 04 September 2005 - 12:25 PM
There's always room for one less, eh?I personally think we have enough globals. We get under each others feet as it is. Though it is up to the almighty Stewart...
Hmmm...

"The mind is like an umbrella, it functions best when open" - Walter Gropius

SNEKK BLOG U-LAR MEKHH! GAHGHH! RK!
GRRGH RGGHH SNORRTT GHACKHGG
Now presented in DoubleVision (where drunk)
#169
Posted 04 September 2005 - 04:25 PM
we have like 4 less GBMs now, and a few more forum mods, but we need to recruit more moderators
i'll still take any open forums
and stewart, if you ever want to be nice, could you give me back labs?
BF2 Hackers =5SF= have busted
]sD[ Engageo <-- couldn't get him banned though, no screenshot of him ingame
]sD[Nomisser
an AK guy
The anti-logarithm of the logarithm of X plus the logarithm of Y equals X times Y, or 10^(logX + logY) = XY

I hate spider solitaire...
#170
Posted 16 September 2005 - 10:17 PM
As for UFO2k I will leave Serge as the lone Global for that.
#172
Posted 16 September 2005 - 11:10 PM
as long as you don't put me in Xcom 4+ i'll be fine, i could probably interest people. The reason why i say no to those xcom's, is because i know nothing about them
thanks though
I'm positive that azrael wouldn't mind me modding them either, as he modded them a while ago too before he was made senior
BF2 Hackers =5SF= have busted
]sD[ Engageo <-- couldn't get him banned though, no screenshot of him ingame
]sD[Nomisser
an AK guy
The anti-logarithm of the logarithm of X plus the logarithm of Y equals X times Y, or 10^(logX + logY) = XY

I hate spider solitaire...
#173
Guest_Azrael_*
Posted 17 September 2005 - 12:08 PM

edit: Why don't you mod (and breathe some life into) UFO: Aftershock? the game is about to be released and I'm jealous of StrategyCore's section on it.
Edited by Azrael, 17 September 2005 - 12:12 PM.
#174
Posted 17 September 2005 - 12:15 PM
the labs need more activity as well, but i could try and kick it in the chest
we need more people coming in as well
BF2 Hackers =5SF= have busted
]sD[ Engageo <-- couldn't get him banned though, no screenshot of him ingame
]sD[Nomisser
an AK guy
The anti-logarithm of the logarithm of X plus the logarithm of Y equals X times Y, or 10^(logX + logY) = XY

I hate spider solitaire...
#175
Guest_Azrael_*
Posted 17 September 2005 - 12:18 PM
Oh, you meant the Labs, well it doesn't matter if I mind or not, that's Red Knight's callLabs, not Workshops, the workshops are offlimits for me, i seriously doubt that anyone would let me, because you don't need help
the labs need more activity as well, but i could try and kick it in the chest
we need more people coming in as well

Edited by Azrael, 17 September 2005 - 12:18 PM.
#176
Posted 17 September 2005 - 11:05 PM
1) Poke RK
2) Poke Department Leader
3) Poke admins, and toss the results of the poking RK and department leader at them
BF2 Hackers =5SF= have busted
]sD[ Engageo <-- couldn't get him banned though, no screenshot of him ingame
]sD[Nomisser
an AK guy
The anti-logarithm of the logarithm of X plus the logarithm of Y equals X times Y, or 10^(logX + logY) = XY

I hate spider solitaire...
#182
Posted 12 March 2006 - 10:20 PM
I don't think that would be a problem, but we'll wait for stewart.Could I moderate Xcom 1 Saved Games and Technical Support as well?
Why? We have 3 moderators there already. TFTD is not busy enough to warrant a 4th IMHO.BTW, I have my sights on TFTD too.

- Zombie
Zombie: Empirical data's your only man, when formulating a research plan.
A soldier's death is never in vain if it makes the formula more plain.
A few dozen make a better case for refining that third decimal place.
They call me Zombie because I don't sleep, as I slowly struggle to climb this heap,
of corpses, data points, and trials, but from the top - I'll see for miles!
#184
Posted 13 March 2006 - 12:10 PM
#185
Posted 17 March 2006 - 12:56 AM

i just noticed that thats about all i say when i ask for new forums <_<
Edited by Blehm 98, 17 March 2006 - 11:33 AM.
BF2 Hackers =5SF= have busted
]sD[ Engageo <-- couldn't get him banned though, no screenshot of him ingame
]sD[Nomisser
an AK guy
The anti-logarithm of the logarithm of X plus the logarithm of Y equals X times Y, or 10^(logX + logY) = XY

I hate spider solitaire...
#188
Posted 18 March 2006 - 12:20 AM

BF2 Hackers =5SF= have busted
]sD[ Engageo <-- couldn't get him banned though, no screenshot of him ingame
]sD[Nomisser
an AK guy
The anti-logarithm of the logarithm of X plus the logarithm of Y equals X times Y, or 10^(logX + logY) = XY

I hate spider solitaire...
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